## Intermediate Algebra (6th Edition)

$a_{21}=19$
Using $a_n=a_1+(n-1)d$ or the $n$th term of an arithmetic sequence, then, \begin{array}{l} a_{21}=14+(21-1)\cdot\dfrac{1}{4} \\ a_{21}=14+5 \\ a_{21}=19 .\end{array}