Answer
$4, 6, 8, 10, 12$
Work Step by Step
The general term $a_n$ of an arithmetic sequence is given by $a_n = a_1 + (n-1)d$ where $a_1$ is the first term and $d$ is the common difference.
We plug in $n = 1, 2, 3, 4, 5$ to find the first five terms of the arithmetic sequence
$a_1 = 4 + (1-1)\cdot2 = 4+0\cdot2 = 4$
$a_2 = 4 + (2-1)\cdot2 = 4+1\cdot2 = 6$
$a_3 = 4 + (3-1)\cdot2 = 4+2\cdot2 = 8$
$a_4 = 4 + (4-1)\cdot2 = 4+3\cdot2 = 10$
$a_5 = 4 + (5-1)\cdot2 = 4+4\cdot2 = 12$
