## Intermediate Algebra (6th Edition)

$6, 4, 2, 0, -2$
The general term $a_n$ of an arithmetic sequence is given by $a_n = a_1 + (n-1)d$ where $a_1$ is the first term and $d$ is the common difference. We plug in $n = 1, 2, 3, 4, 5$ to find the first five terms of the arithmetic sequence $a_1 = 6 + (1-1)\cdot(-2) = 6+0\cdot(-2)= 6$ $a_2 = 6 + (2-1)\cdot(-2) = 6+1\cdot(-2)= 4$ $a_3 = 6 + (3-1)\cdot(-2) = 6+2\cdot(-2)= 2$ $a_4 = 6 + (4-1)\cdot(-2) = 6+3\cdot(-2)= 0$ $a_5 = 6 + (5-1)\cdot(-2) = 6+4\cdot(-2)= -2$