Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 646: 18



Work Step by Step

Using $a_n=a_1r^{n-1}$ or the $n$th term of a geometric sequence, then, \begin{array}{l} a_{9}=5(2)^{9-1} \\ a_{9}=5(256) \\ a_{9}=1,280 .\end{array}
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