Answer
$1,3,9,27,81$
Work Step by Step
The general term $a_n$ of a geometric sequence is given by $a_n = a_1r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio.
We plug in $n = 1, 2, 3, 4, 5$ to find the first five terms of the geometric sequence
$a_1 = 1\cdot3^{1-1} = 1\cdot3^0=1\cdot1=1$
$a_2 = 1\cdot3^{2-1} = 1\cdot3^1=1\cdot3=3$
$a_3 = 1\cdot3^{3-1} = 1\cdot3^2=1\cdot9=9$
$a_4 = 1\cdot3^{4-1} = 1\cdot3^3=1\cdot27=27$
$a_5 = 1\cdot3^{5-1} = 1\cdot3^4=1\cdot81=81$
