Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 646: 14

Answer

$-5120$

Work Step by Step

To find the $n$th term of a geometric sequence, we use the formula $a_n = a_1 \cdot r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio. $a_6 = 5\cdot(-4)^{6-1} = 5\cdot(-4)^5 = 5\cdot(-1024) = -5120$
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