Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 646: 20

Answer

$a_{6}=\dfrac{243}{2}$

Work Step by Step

Using $a_n=a_1r^{n-1}$ or the $n$th term of a geometric sequence, then, \begin{array}{l} a_{6}=\dfrac{1}{2}(3)^{6-1} \\\\ a_{6}=\dfrac{1}{2}(243) \\\\ a_{6}=\dfrac{243}{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.