Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 646: 19

Answer

$a_{5}=1,250$

Work Step by Step

Using $a_n=a_1r^{n-1}$ or the $n$th term of a geometric sequence, then, \begin{array}{l} a_{5}=2(-5)^{5-1} \\ a_{5}=2(625) \\ a_{5}=1,250 .\end{array}
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