Intermediate Algebra (6th Edition)

Published by Pearson

Chapter 11 - Section 11.2 - Arithmetic and Geometric Sequences - Exercise Set - Page 646: 4

Answer

$-20,-17,-14,-11,-8$

Work Step by Step

The general term $a_n$ of an arithmetic sequence is given by $a_n = a_1 + (n-1)d$ where $a_1$ is the first term and $d$ is the common difference. We plug in $n = 1, 2, 3, 4, 5$ to find the first five terms of the arithmetic sequence $a_1 = -20 + (1-1)\cdot3 = -20+0\cdot3 = -20$ $a_2 = -20 + (2-1)\cdot3 = -20+1\cdot3= -17$ $a_3 = -20 + (3-1)\cdot3 = -20+2\cdot3= -14$ $a_4 = -20 + (4-1)\cdot3 = -20+3\cdot3= -11$ $a_5 = -20 + (5-1)\cdot3 = -20+4\cdot3= -8$

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