Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Chapter R-9 - Cumulative Review Exercises - Page 642: 31

Answer

$-27\sqrt{2}$

Work Step by Step

Extracting the factor that is a perfect root of the radical, the given expression, $ 2\sqrt{32}-5\sqrt{98} $, is equivalent to \begin{align*} & 2\sqrt{16\cdot2}-5\sqrt{49\cdot2} \\&= 2\sqrt{16}\cdot\sqrt{2}-5\sqrt{49}\cdot\sqrt{2} \\&= 2(4)\cdot\sqrt{2}-5(7)\cdot\sqrt{2} \\&= 8\sqrt{2}-35\sqrt{2} .\end{align*} Combining like radicals, the expression above is equivalent to \begin{align*} & (8-35)\sqrt{2} \\&= -27\sqrt{2} .\end{align*} Hence, the expression $ 2\sqrt{32}-5\sqrt{98} $ simplifies to $ -27\sqrt{2} $.
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