Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Chapter R-9 - Cumulative Review Exercises - Page 642: 17

Answer

$6p^2+7p-3$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$, the given expression, $ (2p+3)(3p-1) ,$ is equivalent to \begin{align*} & 2p(3p)+2p(-1)+3(3p)+3(-1) \\&= 6p^2-2p+9p-3 \\&= 6p^2+7p-3 .\end{align*} Hence, the expression $(2p+3)(3p-1)$ is equivalent to $ 6p^2+7p-3 $.
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