Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Chapter R-9 - Cumulative Review Exercises - Page 642: 30

Answer

$12\sqrt{2}$

Work Step by Step

Extracting the factor that is a perfect root of the radical, the given expression, $ \sqrt{288} $, is equivalent to \begin{align*} & \sqrt{144\cdot2} \\&= \sqrt{144}\cdot\sqrt{2} \\&= 12\sqrt{2} .\end{align*} Hence, the expression $ \sqrt{288} $ simplifies to $ 12\sqrt{2} $.
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