Answer
$(4a+5b^2)(4a-5b^2)$
Work Step by Step
Using the factoring of the difference of $2$ squares which is given by $a^2-b^2=(a+b)(a-b),$ the given $\text{
expression,
}$ $
16a^2-25b^4
,$ is equivalent to
\begin{align*}
&
(4a)^2-(5b^2)^2
\\&=
(4a+5b^2)(4a-5b^2)
.\end{align*}
Hence, the factored form of $16a^2-25b^4$ is $
(4a+5b^2)(4a-5b^2)
.$