Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Chapter R-9 - Cumulative Review Exercises - Page 642: 24

Answer

$(4a+5b^2)(4a-5b^2)$

Work Step by Step

Using the factoring of the difference of $2$ squares which is given by $a^2-b^2=(a+b)(a-b),$ the given $\text{ expression, }$ $ 16a^2-25b^4 ,$ is equivalent to \begin{align*} & (4a)^2-(5b^2)^2 \\&= (4a+5b^2)(4a-5b^2) .\end{align*} Hence, the factored form of $16a^2-25b^4$ is $ (4a+5b^2)(4a-5b^2) .$
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