Answer
$\frac{(5x +2 )}{(x-3)}$
Work Step by Step
$\frac{5x}{x-3} + \frac{2}{x} + \frac{6}{x^2 - 3x}$
$=\frac{5x}{x-3} + \frac{2}{x} + \frac{6}{x(x - 3)}$
$=\frac{5x\times x + 2\times (x-3) + 6}{x(x-3)}$
$=\frac{5x^2 +2 x}{x(x-3)}$
$=\frac{x(5x +2 )}{x(x-3)}$
$=\frac{(5x +2 )}{(x-3)}$
