Answer
$\frac{7-4a^{2}b}{18a^{3}b^{2}}$
Work Step by Step
$\frac{7}{18a^{3}b^{2}}-\frac{2}{9ab}=\frac{7}{18a^{3}b^{2}}-\frac{2\times2a^{2}b}{9ab\times2a^{2}b}=\frac{7}{18a^{3}b^{2}}-\frac{4a^{2}b}{18a^{3}b^{2}}=\frac{7-4a^{2}b}{18a^{3}b^{2}}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 383: 46
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