Answer
$\frac{2x+3}{x(x-3)}$
Work Step by Step
$\frac{3}{x-3}-\frac{1}{x}=\frac{3\times x}{(x-3)\times x}-\frac{1\times(x-3)}{x\times(x-3)}=\frac{3x}{x(x-3)}-\frac{x-3}{x(x-3)}=\frac{3x-(x-3)}{x(x-3)}=\frac{3x-x+3}{x(x-3)}=\frac{2x+3}{x(x-3)}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 383: 54
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