Answer
$\dfrac{5x^2 -2x}{(x+4) (x-7)}$
Work Step by Step
$\frac{2x}{x+4} + \frac{3x}{x-7}$
$=\frac{2x \times (x-7)}{(x+4) \times (x-7)} + \frac{3x \times (x+4)}{(x-7) \times (x+4)}$
$=\frac{2x^2 -14x + 3x^2 +12x}{(x+4) (x-7)}$
$=\frac{5x^2 -2x}{(x+4) (x-7)}$
