Answer
$\dfrac{-x^2 + x - 30}{(x+3)(x-3)}$
Work Step by Step
$\frac{4}{x+3} - \frac{x}{x-3} - \frac{18}{x^2 - 9}$
$=\frac{4}{x+3} - \frac{x}{x-3} - \frac{18}{(x+3)(x-3)}$
$=\frac{4 \times (x-3) - (x\times (x+3)) - 18}{(x+3)(x-3)}$
$=\frac{4x -12 - x^2 - 3x - 18}{(x+3)(x-3)}$
$=\frac{-x^2 + x - 30}{(x+3)(x-3)}$
