Answer
$\dfrac{4}{(t-2)}$
Work Step by Step
$\frac{7}{t-2} - \frac{6}{t^2 -2t } - \frac{3}{t}$
$=\frac{7}{t-2} - \frac{6}{t(t -2) } - \frac{3}{t}$
$=\frac{7t - 6 - 3 \times (t-2)}{t(t-2)}$
$=\frac{4t}{t(t-2)}$
$=\frac{4}{(t-2)}$
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