Answer
$\frac{-4}{(x-1)(x+1)}$
Work Step by Step
$\frac{-2}{x-1} + \frac{2}{x+1}$
$=\frac{-2 \times (x+1)}{(x-1) \times (x+1)} + \frac{2 \times (x-1)}{(x+1) \times (x-1)}$
$=\frac{-2x -2 + 2x -2}{(x-1)(x+1)}$
$=\frac{-4}{(x-1)(x+1)}$
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