Answer
$\frac{-2}{t-2}$
Work Step by Step
$\frac{3}{2-t} + \frac{1}{t-2}$
$=\frac{3 \times (-1)}{(2-t) \times (-1)} + \frac{1}{t-2}$
$=\frac{-3}{t-2} + \frac{1}{t-2}$
$=\frac{-3 + 1}{t-2}$
$=\frac{-2}{t-2}$ or $\frac{2}{2-t}$
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