Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 383: 48

Answer

$\frac{15y^3 + 10x}{36x^5y^5}$

Work Step by Step

$\dfrac{5}{12x^5y^2} + \dfrac{5}{18x^4y^5}$ $= \dfrac{5\times 3y^3}{12x^5y^2 \times 3y^3 } + \dfrac{5\times 2x}{18x^4y^5 \times 2x}$ $= \dfrac{15y^3 + 10x}{36x^5y^5}$
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