Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 383: 55

Answer

$\dfrac{a(5a - 7)}{(a+1)(a-3)}$

Work Step by Step

$\frac{3a}{a+1} + \frac{2a}{a-3}$ $= \frac{3a \times (a-3)}{(a+1) \times (a-3)} + \frac{2a \times (a+1)}{(a-3) \times (a+1)}$ $= \frac{3a^2 - 9a + 2a^2 +2a}{(a+1)(a-3)}$ $= \frac{5a^2 - 7a}{(a+1)(a-3)}$ $= \frac{a(5a - 7)}{(a+1)(a-3)}$
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