Answer
$\dfrac{-2}{(x-1)(x+1)}$
Work Step by Step
$\frac{1}{x+1} - \frac{1}{x-1}$
$=\frac{1 \times (x-1)}{(x+1) \times (x-1)} - \frac{1 \times(x+1)}{(x-1) \times(x+1)}$
$=\frac{x- 1 - (x+1)}{(x-1)(x+1)}$
$=\frac{-2}{(x-1)(x+1)}$
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