Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - 6.2 Exercises - Page 383: 47

Answer

$\frac{16b + 9 a^2}{60a^4b^6}$

Work Step by Step

$\frac{4}{15a^4b^5} + \frac{3}{20a^2b^6}$ $= \frac{4\times 4\times b + 3\times 3 \times a^2}{60a^4b^6}$ $= \frac{16b + 9 a^2}{60a^4b^6}$
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