## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set: 88

#### Answer

$\dfrac{a^{10}}{3b^{9}c^{2}}$

#### Work Step by Step

Using the laws of exponents, the given expression, $\dfrac{9a^6b^{-4}c^7}{27a^{-4}b^5c^9}$, is equivalent to \begin{array}{l}\require{cancel} \dfrac{\cancel{9}a^{6-(-4)}b^{-4-5}c^{7-9}}{\cancel{9}\cdot3} \\\\= \dfrac{a^{10}b^{-9}c^{-2}}{3} \\\\= \dfrac{a^{10}}{3b^{9}c^{2}} .\end{array}

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