## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

A bird's heart beats around 600 times per minute. This is equivalent to about 10 heartbeats per second. Thus, the time between heartbeats is around one-tenth of a second. There are 3600 seconds in one hour. Hence, $\dfrac{1}{10} \text{ of a second} = \dfrac{\frac{1}{10}}{3600}\text{ of an hour}=\dfrac{1}{36000} \text{ of an hour}$. Since the measurement is a very small number, then its equivalent scientific notation will involve a negative power of 10.