Answer
Option (b)
Work Step by Step
Use the rule $\left(\frac{a}{b}\right)^m=\frac{a^m}{b^m}$ to obtain:
$=\dfrac{(x^{-3})^{-3}}{(y^{-2})^{-3}}$
Use the rule $(a^m)^n=a^{mn}$
$=\dfrac{x^{-3(-3)}}{y^{-2(-3)}}
\\=\dfrac{x^9}{y^6}$
Thus, the answer is Option (b).