Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set: 65

Answer

$-\dfrac{3a^{2}}{2}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{-15a^{-7}}{10b^{-9}} $, is equivalent to \begin{array}{l}\require{cancel} \dfrac{\cancel{5}\cdot(-3)a^{-7-(-9)}}{\cancel{5}\cdot2} \\\\= \dfrac{-3a^{-7+9}}{2} \\\\= -\dfrac{3a^{2}}{2} .\end{array}
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