Answer
$\dfrac{1}{x^{11}}$
Work Step by Step
Using the laws of exponents, the given expression, $
x^{-4}\cdot x^{-7}
$, is equivalent to
\begin{array}{l}
x^{-4+(-7)}
\\\\=
x^{-4-7}
\\\\=
x^{-11}
\\\\=
\dfrac{1}{x^{11}}
.\end{array}
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