Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set - Page 244: 23

Answer

$a^8$

Work Step by Step

Using $\dfrac{1}{a^{-x}}=a^x$, the given expression, $ \dfrac{1}{a^{-8}} $, is equivalent to \begin{array}{l} a^8 .\end{array}
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