## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{1}{n^{15}}$
Using the laws of exponents, the given expression, $(n^{-5})^3$, is equivalent to \begin{array}{l} n^{-5(3)} \\\\= n^{-15} \\\\= \dfrac{1}{n^{15}} .\end{array}