## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{1}{m^{7}n^{7}}$
Using the laws of exponents, the given expression, $(mn)^{-7}$, is equivalent to \begin{array}{l} m^{-7}n^{-7} \\\\= \dfrac{1}{m^{7}n^{7}} .\end{array}