## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{4a^3c^{3}}{5b^{2}}$
Using the laws of exponents, the given expression, $\left( \dfrac{4a^3b^{-2}}{5c^{-3}} \right)^{1}$, is equivalent to \begin{array}{l}\require{cancel} \dfrac{4a^3b^{-2}}{5c^{-3}} \\\\= \dfrac{4a^3c^{3}}{5b^{2}} .\end{array}