## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Use the rule $\left(\frac{a}{b}\right)^m=\frac{a^m}{b^m}$ to obtain: $=\dfrac{(y^{-2})^{-3}}{(x^{-3})^{-3}}$ Use the rule $(a^m)^n=a^{mn}$ $=\dfrac{y^{-2(-3)}}{x^{-3(-3)}} \\=\dfrac{y^6}{x^9}$ Thus, the answer is Option (a).