Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

RECALL: A negative exponent means reciprocal. Thus, $a^{-m} = \frac{1}{a^m}=(\frac{1}{a})^m$. Using the rule above gives: $(\frac{x^3}{y^2})^{-2}=(\frac{y^2}{x^3})^2$ Simplify using the rule $(a^m)^n=a^{mn}$ to obtain: $=\dfrac{y^{2(2)}}{x^{3(2)}} \\=\dfrac{y^4}{x^6}$ Thus, the answer is Option (c).