Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set - Page 244: 6


Option (d)

Work Step by Step

RECALL: A negative exponent means reciprocal. Thus, $a^{-m} = \frac{1}{a^m}=(\frac{1}{a})^m$. Using the rule above gives: $(\frac{y^2}{x^3})^{-2}=(\frac{x^3}{y^2})^2$ Simplify using the rule $(a^m)^n=a^{mn}$ to obtain: $=\dfrac{x^{3(2)}}{y^{2(2)}} \\=\dfrac{x^6}{y^4}$ Thus, the answer is Option (d).
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