Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.8 Problem Solving and Quadratic Functions - 11.8 Exercise Set - Page 756: 50

Answer

$y=-4$.

Work Step by Step

Horizontal line passing through the point $\left( 7,-4 \right)$. The line is horizontal; therefore, its slope is zero. Put the provided values in the point slope form of a straight line $\left( y-{{y}_{1}} \right)=m\left( x-{{x}_{1}} \right)$. $\begin{align} & \left( y-{{y}_{1}} \right)=m\left( x-{{x}_{1}} \right) \\ & y-\left( -4 \right)=0\left( x-7 \right) \\ & y=-4 \end{align}$ Thus, the equation in slope-intercept form of a line is $y=-4$.
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