Answer
$y=-\frac{4}{3}x+\frac{40}{3}$.
Work Step by Step
The line passes through the points $\left( 4,8 \right)$ and $\left( 10,0 \right)$.
Find the value of $m$.
$\begin{align}
& m=\frac{0-8}{10-4} \\
& =-\frac{8}{6} \\
& =-\frac{4}{3}
\end{align}$
Put the values into the equation of a straight line.
$\begin{align}
& y-0=-\frac{4}{3}\left( x-10 \right) \\
& y=\frac{4}{3}x+\frac{40}{3}
\end{align}$
Thus, the equation in slope-intercept form of a line with the points $\left( 4,8 \right)$ and $\left( 10,0 \right)$ is $y=-\frac{4}{3}x+\frac{40}{3}$.
