Chapter 11 - Quadratic Functions and Equations - 11.8 Problem Solving and Quadratic Functions - 11.8 Exercise Set - Page 756: 45

$y=-\frac{1}{3}x+16$.

Slope: $-\frac{1}{3}$; y-intercept: $\left( 0,16 \right)$. Put the values in the equation of a straight line $y=mx+b$. $y=-\frac{1}{3}x+16$ Thus, the equation becomes: Slope: $-\frac{1}{3}$ and y-intercept: $\left( 0,16 \right)$ $y=-\frac{1}{3}x+16$.