Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.8 Problem Solving and Quadratic Functions - 11.8 Exercise Set - Page 756: 49

Answer

$y=\frac{1}{2}x-6$.

Work Step by Step

Want: Perpendicular to the line $2x+y=3$ and a y-intercept that is $\left( 0,-6 \right)$. Solve further. $\begin{align} & 2x+y=3 \\ & y=-2x+3 \end{align}$ Slope of the provided line is $-2$ and the product of the slope of the lines perpendicular to each other results equal to $-1$. That is, $\begin{align} & -2\cdot m=-1 \\ & m=\frac{1}{2} \end{align}$ Slope of the required line is $m=\frac{1}{2}$. Put the provided values in the straight line equation. $y=\frac{1}{2}x-6$
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