Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.8 Problem Solving and Quadratic Functions - 11.8 Exercise Set - Page 756: 46

Answer

$y=2x+13$.

Work Step by Step

Slope: $2$; contains point $\left( -3,7 \right)$. Put the values in the point slope form of straight line. $\begin{align} & \left( y-{{y}_{1}} \right)=m\left( x-{{x}_{1}} \right) \\ & y-7=2\left( x+3 \right) \end{align}$ Simplify further. $\begin{align} & y-7=2x+6 \\ & y=2x+13 \end{align}$ Thus, the equation in slope-intercept form of the line is $y=2x+13$.
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