Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 9



Work Step by Step

Recall, when a number is raised to the second power, the square root cancels out the exponent, and when a number is raised to the third power, the cube root cancels out the exponent. Thus, we obtain: $ \sqrt[3] {64}/\sqrt{49} = \sqrt[3] {4^{3}}/ \sqrt{7^{2}}=4/7$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.