# Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 9

4/7

#### Work Step by Step

Recall, when a number is raised to the second power, the square root cancels out the exponent, and when a number is raised to the third power, the cube root cancels out the exponent. Thus, we obtain: $\sqrt[3] {64}/\sqrt{49} = \sqrt[3] {4^{3}}/ \sqrt{7^{2}}=4/7$

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