Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 62



Work Step by Step

Recall the following rule: $a^{n}\cdot a^{m}=a^{n+m}$. Therefore, we obtain: $(7n^{-\frac{1}{3}})(8n^{\frac{5}{6}})$ $=(7\times8)(n^{-\frac{1}{3}+\frac{5}{6}})$ $=(56)(n^{\frac{-2+5}{6}})$ $=56n^{\frac{3}{6}}$ $=56n^{\frac{1}{2}}$
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