Answer
$a^{\frac{17}{12}}$
Work Step by Step
Recall the following rule: $a^{n}+a^{m}=a^{n+m}$
Thus, we obtain:
$a^{\frac{2}{3}}\times a^{\frac{3}{4}}$
=$a^{\frac{2}{3}+\frac{3}{4}}$
=$a^{\frac{2(4)+3(3)}{12}}$
=$a^{\frac{8+9}{12}}$
=$a^{\frac{17}{12}}$
