Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 34

Answer

-1024

Work Step by Step

Recall the formula:$ a^{b/c}=( \sqrt[c] {a})^{b}$. Thus, we obtain: $-(16^{5/2})=-(\sqrt[2] {16})^{5}=-(4^{5})=-1024$
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