Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3: 54

Answer

$a^{\frac{1}{12}}$

Work Step by Step

Recall the following rule: $a^{n}+a^{m}=a^{n+m}$ Thus, we obtain: $a^{\frac{1}{3}}\times a^{-\frac{1}{4}}$ =$a^{\frac{1}{3}-\frac{1}{4}}$ =$a^{\frac{1(4)-1(3)}{12}}$ =$a^{\frac{4-3}{12}}$ =$a^{\frac{1}{12}}$
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