Answer
$3x^{-\frac{1}{10}}$
Work Step by Step
We will use the rule $a^{n}a^{m}=a^{n+m}$ in the solution. Therefore,
$(x^{\frac{2}{5}})(3x^{-\frac{1}{2}})$
$=(1\times3)(x^{\frac{2}{5}-\frac{1}{2}})$
$=(3)(x^{\frac{2(2)-5}{10}})$
$=3x^{\frac{4-5}{10}}$
$=3x^{-\frac{1}{10}}$
