Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3: 63

Answer

$2x^{\frac{-1}{6}}$

Work Step by Step

We will use the rule $a^{n}a^{m}=a^{n+m}$ in the solution. Therefore, $(2x^{\frac{1}{3}})(x^{-\frac{1}{2}})$ $=(2\times1)(x^{\frac{1}{3}-\frac{1}{2}})$ $=(2)(x^{\frac{2-3}{6}})$ $=2x^{\frac{-1}{6}}$
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