Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 66



Work Step by Step

Raising each term in the expression to the power of $3$, we obtain: $(2x^{\frac{1}{3}}y^{2})^{3}$ =$(2)^{3}(x^{\frac{1}{3}})^{3}(y^{2})^{3}$ =$8(x^{\frac{1}{3}\times3})y^{6}$ =$8(x^{1})(y)^{6}$ =$8xy^{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.